by Din » Thu Jul 16, 2015 12:48 pm
Well, Martin is probably the best person to answer this.
But, taking a bit of a speculative stab at it, Li is further up the periodic table than K. The purpose of the Br ion is to re-halogenate the silver speck. Since Li is further up the table, I would assume that it has a lower disassociatian energy and so forms ions morer readily. Thus, LiBr would produce more Br(-) ions, and so the probablity of capture by a silver speck is increased. Based on this argument, I would assume that LiBr is a better rehalogenating agent. But, it's probably also more reactive and I assume that if you have too many Br ions, then the chances of releasing HBr also increases, and that's probably not a good thing.
Martin?
Well, Martin is probably the best person to answer this.
But, taking a bit of a speculative stab at it, Li is further up the periodic table than K. The purpose of the Br ion is to re-halogenate the silver speck. Since Li is further up the table, I would assume that it has a lower disassociatian energy and so forms ions morer readily. Thus, LiBr would produce more Br(-) ions, and so the probablity of capture by a silver speck is increased. Based on this argument, I would assume that LiBr is a better rehalogenating agent. But, it's probably also more reactive and I assume that if you have too many Br ions, then the chances of releasing HBr also increases, and that's probably not a good thing.
Martin?