Search found 48 matches
Re: opal
So here I display a photograph of a reflection hologram of the Australian black opal with strong red play-of-color. The hologram is illuminated by a white LED light almost exactly as the opal itself was. So... seems like no big deal, a reflection hologram made using a red laser. But take a closer lo...
opal
In this post I display a photograph of an Australian black opal with strong red play-of-color sitting on a black acrylic plate. The elliptical opal is about 1 cm along its major axis. In the photograph, the opal is illuminated by a white light LED from below, tilted toward the opal at an angle of ab...
- Thu Jul 19, 2018 6:21 pm
- Forum: Beginning Holography
- Topic: Fundamentals of Photonics Volume 1
- Replies: 28
- Views: 18276
Re: Fundamentals of Photonics Volume 1
Units help :) Agreed. ... you can get some basics even from Goodman's Introduction to Fourier Optics, chapter on Holography. Optical Holography by Collier et al. is OK as well. Practical Volume Holography by Syms is also worth checking. Thank you for the recommendations. I will look into them.
- Thu Jul 19, 2018 4:14 pm
- Forum: Beginning Holography
- Topic: Fundamentals of Photonics Volume 1
- Replies: 28
- Views: 18276
Re: Fundamentals of Photonics Volume 1
By the way, Brian, is this one of your "One question every week"? :) Very true that I haven't been on the forum in quite some time. So catching up, the energy conservation teaser caught my eye, as I have posited it to my students. But all the while I have been making small reflection holo...
- Wed Jul 18, 2018 3:50 pm
- Forum: Beginning Holography
- Topic: Fundamentals of Photonics Volume 1
- Replies: 28
- Views: 18276
Re: Fundamentals of Photonics Volume 1
"In the areas where the light waves from S are in phase with those from S1¢, the total amplitude is doubled." But, the intensity, which is what's being recorded, is quadrupled, assuming equal intensities: I(t) = I(1) + I(2) + 2√[(I(1)I(2)]cos(φ) If I(1) = I(2) = I, and φ = 2nπ, then I(t) ...
- Thu Jan 05, 2017 6:23 pm
- Forum: General Holography
- Topic: Taming the divergence of a 315M
- Replies: 5
- Views: 4055
Re: Taming the divergence of a 315M
Haha, who knew contour integration could be time dependent?Din wrote: As for contour integration: Why is the contour integral around Western Europe zero? Because all the poles are in Eastern Europe. Ba-Da-Boom!
- Fri Dec 16, 2016 11:27 pm
- Forum: General Holography
- Topic: Taming the divergence of a 315M
- Replies: 5
- Views: 4055
Re: Taming the divergence of a 315M
I really, really wish I could gave differentiated something or integrated something! Oh! I guess I haven't tried to impress anyone, much less me, I think series expansions and basis set expansions are much more impressive. I have a lot more trouble getting my students to perform binomial expansions...
- Fri Dec 16, 2016 11:12 pm
- Forum: Beginning Holography
- Topic: diffraction gratings
- Replies: 12
- Views: 7742
Re: diffraction gratings
Ed, I'm pretty sure the spectral lamp is krypton. Like 99% sure. The only thing preventing me from being 100% sure is that no sane person would use krypton for a discrete line demonstration. After making a few, we gave up on the large divergence gratings. Setting the plate so far from the divergence...
- Tue Nov 29, 2016 11:49 am
- Forum: Beginning Holography
- Topic: diffraction gratings
- Replies: 12
- Views: 7742
Re: diffraction gratings
Thanks Dinesh! We found the first attempt had ~1400 lines/mm. Lots to explore and improve with this setup, so we'll continue with it for the rest of the semester.
- Fri Nov 18, 2016 10:06 am
- Forum: Beginning Holography
- Topic: diffraction gratings
- Replies: 12
- Views: 7742
Re: diffraction gratings
Just for fun, a picture of the setup before we put down the black cloth. Objective-pinhole seen in the foreground. At the far right is reflected light from the mirror, showing the shadow outline of the plate.